Question 1

A bottler of drinking water fills plastic bottles with a mean volume of 993 milliliters(mL) and standard deviation 6 mL. The fill volumes are normally distributed. Whatproportion of bottles have volumes between 991 mL and 997 mL?

Accepted Answer

A)  0.3779
B)  0.7486
C)  0.3707
D)  0.3377E) All of the above
F) A) and B)

Question 2

A bottler of drinking water fills plastic bottles with a mean volume of 999 milliliters (mL)  and standard deviation 4 mL. The fill volumes are normally distributed. What proportion of bottles have volumes greater than 994 mL?

Accepted Answer

A)  1.0000
B)  0.8944
C)  0.9599
D)  0.8925E) A) and B)
F) B) and C)

Question 3

Use the Central Limit Theorem to find the indicated probability. The sample size is  n , the population proportion is   p^\hat { p }p^​  , and the sample proportion is
  0.3 ) ">n=160,p=0.29;P(p^>0.3) n = 160 , p = 0.29 ; P ( \hat { p } > 0.3 ) n=160,p=0.29;P(p^​>0.3)

Accepted Answer

A)    0.6103 
B)    0.3483 
C)    0.3300 
D)    0.3897  E) None of the above
F) B) and C)

Question 4

The mean annual income for people in a certain city (in thousands of dollars)  is 42, with a standard deviation of 38. A pollster draws a sample of 40 people to interview. What is the probability that the sample mean income is less than 35 (thousands of dollars)

Accepted Answer

A)  0.8554
B)  0.1210
C)  0.1446
D)  0.0934E) A) and B)
F) B) and C)

Question 5

Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample.
 n=103,p=0.62:P(X≥61) n = 103 , p = 0.62 : P ( X \geq 61 ) n=103,p=0.62:P(X≥61)

Accepted Answer

A)    0.7611 
B)    0.2743 
C)    0.7517 
D)    0.7257  E) B) and C)
F) None of the above

Exam 7: Confidence Intervals

A bottler of drinking water fills plastic bottles with a mean volume of 999 milliliters (mL) and standard deviation 4 mL. The fill volumes are normally distributed. What proportion of bottles have volumes greater than 994 mL?

Correct Answer
verified

A bottler of drinking water fills plastic bottles with a mean volume of 993 milliliters(mL) and standard deviation 6 mL. The fill volumes are normally distributed. Whatproportion of bottles have volumes between 991 mL and 997 mL?

Correct Answer
verified

The mean annual income for people in a certain city (in thousands of dollars) is 42, with a standard deviation of 38. A pollster draws a sample of 40 people to interview. What is the probability that the sample mean income is less than 35 (thousands of dollars)

Correct Answer
verified

Use the Central Limit Theorem to find the indicated probability. The sample size is n , the population proportion is $\hat { p }$ , and the sample proportion is $n = 160 , p = 0.29 ; P ( \hat { p } > 0.3 )$

Correct Answer
verified

Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. $n = 103 , p = 0.62 : P ( X \geq 61 )$

Correct Answer
verified

Exam 7: Confidence Intervals

A bottler of drinking water fills plastic bottles with a mean volume of 999 milliliters (mL) and standard deviation 4 mL. The fill volumes are normally distributed. What proportion of bottles have volumes greater than 994 mL?

Correct AnswerverifiedShow Answer

A bottler of drinking water fills plastic bottles with a mean volume of 993 milliliters(mL) and standard deviation 6 mL. The fill volumes are normally distributed. Whatproportion of bottles have volumes between 991 mL and 997 mL?

Correct AnswerverifiedShow Answer

The mean annual income for people in a certain city (in thousands of dollars) is 42, with a standard deviation of 38. A pollster draws a sample of 40 people to interview. What is the probability that the sample mean income is less than 35 (thousands of dollars)

Correct AnswerverifiedShow Answer

Use the Central Limit Theorem to find the indicated probability. The sample size is n , the population proportion is p^\hat { p }p^​ , and the sample proportion is n=160,p=0.29;P(p^>0.3) n = 160 , p = 0.29 ; P ( \hat { p } > 0.3 ) n=160,p=0.29;P(p^​>0.3)

Correct AnswerverifiedShow Answer

Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. n=103,p=0.62:P(X≥61) n = 103 , p = 0.62 : P ( X \geq 61 ) n=103,p=0.62:P(X≥61)

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Use the Central Limit Theorem to find the indicated probability. The sample size is n , the population proportion is $\hat { p }$ , and the sample proportion is $n = 160 , p = 0.29 ; P ( \hat { p } > 0.3 )$

Correct Answer
verified

Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. $n = 103 , p = 0.62 : P ( X \geq 61 )$

Correct Answer
verified