A) bacteriophage.
B) Drosophila.
C) frog eggs.
D) Streptococcus.
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A) genes
B) DNA
C) RNA
D) chromosomes
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Multiple Choice
A) AAAACGCCA.
B) TTAACGGCT.
C) TTAACGGCA.
D) TTAAGCCGA.
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A) 1' end.
B) 2' end.
C) 3' end.
D) 4' enD.
E) 5' end.
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A) parental DNA.
B) Chargaff's segments.
C) repeating primers.
D) replisomes.
E) Okazaki fragments.
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Multiple Choice
A) The two strands are separated.
B) Each strand is used as a template for making a new duplex.
C) The synthesis on each strand is in the opposite direction.
D) The newly synthesized DNA is packaged into one nucleus,and the old DNA is packaged into another nucleus.
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A) Hershey and Chase
B) Chargaff
C) Franklin
D) Watson and Crick
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A) 8'
B) 3'
C) 5'
D) 1'
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Multiple Choice
A) 5' ATGGTCAGT 3'
B) 5' TGACTGGTA 3'
C) 5' TACCAGTCA 3'
D) 5' ACTGACCAT 3'
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A) circle
B) helix
C) double helix
D) double pleated sheet
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Multiple Choice
A) Hershey and Chase
B) Chargaff
C) Franklin
D) Watson and Crick
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Multiple Choice
A) photolyase-induced mutations
B) decreased telomere length
C) thymine dimers
D) uvr A,B,and C
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Multiple Choice
A) The DNA replication would proceed except that all adenine would have the chemical bound to it and is incorporated into the new sister chromatids.
B) The DNA replication would proceed except that everywhere an adenine was supposed to be,a thymine was substituted into the new developing strand.
C) The DNA replication would proceed except cytosine and guanine would continue to form base pairs.
D) The DNA replication would stop because if adenine were bound then thymine would not have a complement with which to base pair.
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A) 8'
B) 3'
C) 5'
D) 1'
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A) elimination of the initiation phase,thus shorten the length of the replication process.
B) producing several sliding clamp complexes that allow DNA pol III enzymes more binding sites.
C) allowing DNA gyrase to unravel the double helix faster than the DNA helicase,which then speeds up the formation of the replication folk.
D) using multiple origins of the replication on each chromosome,which results in multiple replicons.
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Multiple Choice
A) creates a short RNA primer complementary to the RNA template.
B) creates a short DNA primer complementary to the RNA template.
C) creates a short DNA primer complementary to the DNA template.
D) creates a short template of an RNA primer that is complementary to the DNA primer.
E) creates a short RNA primer complementary to the DNA templatE.
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Multiple Choice
A) the ability for bacterial homologous chromosomes to transform themselves into an exact copy,sometimes referred to as DNA replication.
B) the ability of the nucleus of a cell to regenerate and repair itself when damaged by bacterial infections.
C) the ability of the infected mice to transform the bacteria from pathogenic to non-pathogenic during the experiments.
D) the ability to transfer genetic materials from one cell to another.
E) the ability for the nucleus of a bacterial cell to bypass the process of DNA replication by transforming into a spore during unsuitable environmental conditions.
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A) defects in DNA repair
B) defects in DNA replication
C) lack of telomerase activity
D) shortened telomeres
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Multiple Choice
A) initiation,termination,elongation
B) initiation,elongation,termination
C) elongation,termination,initiation
D) elongation,initiation,termination
E) coli?
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Multiple Choice
A) It allows the width between the phosphate strands to remain consistent.
B) It is essential for proper base pairing of A with T and C with G.
C) The presence of additional tautomeric forms would violate Chargaff's rules.
D) The presence of additional tautomeric forms would cause the two DNA strands to form a parallel configuration rather than an antiparallel configuration.
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